6(a+2)=4[a-(10-a)]

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Solution for 6(a+2)=4[a-(10-a)] equation:


Simplifying
6(a + 2) = 4[a + -1(10 + -1a)]

Reorder the terms:
6(2 + a) = 4[a + -1(10 + -1a)]
(2 * 6 + a * 6) = 4[a + -1(10 + -1a)]
(12 + 6a) = 4[a + -1(10 + -1a)]
12 + 6a = 4[a + (10 * -1 + -1a * -1)]
12 + 6a = 4[a + (-10 + 1a)]

Reorder the terms:
12 + 6a = 4[-10 + a + 1a]

Combine like terms: a + 1a = 2a
12 + 6a = 4[-10 + 2a]
12 + 6a = [-10 * 4 + 2a * 4]
12 + 6a = [-40 + 8a]

Solving
12 + 6a = -40 + 8a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-8a' to each side of the equation.
12 + 6a + -8a = -40 + 8a + -8a

Combine like terms: 6a + -8a = -2a
12 + -2a = -40 + 8a + -8a

Combine like terms: 8a + -8a = 0
12 + -2a = -40 + 0
12 + -2a = -40

Add '-12' to each side of the equation.
12 + -12 + -2a = -40 + -12

Combine like terms: 12 + -12 = 0
0 + -2a = -40 + -12
-2a = -40 + -12

Combine like terms: -40 + -12 = -52
-2a = -52

Divide each side by '-2'.
a = 26

Simplifying
a = 26

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